Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool valid(TreeNode* node, TreeNode* &pre) {
if(node==NULL) return true;
if(valid(node->left, pre)) {
if(pre!=NULL && pre->val >= node->val) return false;
pre=node;
return valid(node->right, pre);
}
return false;
}
bool isValidBST(TreeNode* root) {
if(root == NULL) return true;
TreeNode *pre=NULL;
return valid(root, pre);
}
};