python获取文件路径

<code class="language-python">import os

base_dir = os.path.dirname(__file__)

# 获取当前文件目录

path = os.path.join(base_dir,'123.txt')

https://www.jb51.net/article/149348.htm

os.path.join()函数：连接两个或更多的路径名组件

1.如果各组件名首字母不包含'/'，则函数会自动加上

demo1

1 2 3 4 5 6 7 8

import os Path1 = 'home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1,Path2,Path3) print ('Path10 = ',Path10) print ('Path20 = ',Path20)

输出：

Path10 =  homedevelopcode
Path20 =  home\develop\code

2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃

demo2

1 2 3 4 5 6 7 8 9 10

import os Path1 = '/home' Path2 = 'develop' Path3 = 'code' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1, Path2, Path3) Path30 = os.path.join(Path2, Path1, Path3) print('Path10 = ',Path10) print('Path20 = ',Path20) print('Path30 = ',Path30)

　输出：

Path10 =  /homedevelopcode
Path20 =  /home\develop\code
Path30 =  /home\code

3.如果最后一个组件为空，则生成的路径以一个'/'分隔符结尾

demo3

1 2 3 4 5 6 7 8 9

import os Path1 = 'home' Path2 = 'develop' Path3 = '' Path10 = Path1 + Path2 + Path3 Path20 = os.path.join(Path1, Path2, Path3) Path30 = os.path.join(Path2, Path1, Path3) print('Path10 = ',Path10) print('Path20 = ',Path20)

输出：

Path10 =  homedevelop
Path20 =  home\develop\

总结

以上所述是小编给大家介绍的python路径拼接os.path.join()函数的用法,希望对大家有所帮助

https://www.jb51.net/article/171478.htm