#include <iostream>
#include <istream>
#include <sstream>
#include <vector>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <deque>
#include <queue>
#include <cstring>
#include <unordered_map>
#include <unordered_set>
#include <algorithm>
#include <numeric>
#include <chrono>
#include <ctime>
#include <cmath>
#include <cctype>
#include <string>
#include <cstdio>
#include <iomanip>
#include <thread>
#include <mutex>
#include <condition_variable>
#include <functional>
#include <iterator>
using namespace std;
long long int result[256],temp[256];
unordered_set<long long int > noUse;
int maxn;
long long int gcd(long long int a, long long int b) {
return b == 0 ? a : gcd(b, a % b);
}
long long int GetFirst(long long int a, long long int b) {
return ceil(b * 1.0/ a);
}
bool dfs(long long int a, long long int b, int cur, long long int first) {
if (cur == 0) {
if (a == 0) {
//最小的分数越大越好
bool isBig = false;
for (int i = maxn - 1; i >= 0; i--) {
if(temp[i] == result[i]) continue;
if (result[i] == -1 || temp[i] < result[i]) {
isBig = true;
}
break;
}
if (isBig) memmove(result, temp, sizeof(result));
return true;
}
return false;
}
long long int start = max(first, GetFirst(a, b));
bool ret = false;
for (long long int i = start; ; i++) {
if (a * i > b * cur)break;
if (noUse.find(i) != noUse.end())continue;
long long int nb = b * i;
long long int na = a * i - b;
long long int nc = gcd(na, nb);
na /= nc;
nb /= nc;
temp[maxn - cur] = i;
if (dfs(na, nb, cur - 1, i + 1)) ret = true;
}
return ret;
}
int main()
{
int n,a,b,id = 0,cnt,t;
cin >> n;
while (n--) {
noUse.clear();
memset(result, -1, sizeof(result));
cin >> a >> b >> cnt;
for (int i = 0; i < cnt; i++) {
cin >> t;
noUse.insert(t);
}
for ( maxn = 1;; maxn++) {
if(dfs(a,b, maxn,GetFirst(a,b))) break;
}
cout << "Case " << ++id << ": " << a << "/" << b << "=";
for (int i = 0; i < maxn; i++) {
if (i)cout << "+";
cout << "1/" << result[i];
}
cout << endl;
}
return 0;
}
习题7-7(uva-12558)
最新推荐文章于 2023-11-13 10:10:07 发布
该博客主要介绍了一个C++程序,通过深度优先搜索(DFS)解决寻找最简分数组合的问题。程序首先定义了计算最大公约数(GCD)的函数,然后利用DFS遍历所有可能的分数组合,避免使用给定的禁止项,并找到最小的分数表示。最终,程序会输出一个最简分数序列来表示给定的两个整数比。
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