Problem Description
Chiaki often participates in international competitive programming contests. The time zone becomes a big problem.
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone s .
Input
There are multiple test cases. The first line of input contains an integer T (1≤T≤106 ), indicating the number of test cases. For each test case:
The first line contains two integers a , b (0≤a≤23,0≤b≤59 ) and a string s in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤9 ).
Output
For each test, output the time in the format of hh:mm (24-hour clock).
Sample Input
3 11 11 UTC+8 11 12 UTC+9 11 23 UTC+0
Sample Output
11:11 12:12 03:23
第一次做
没想到全部转化成分钟处理要简单得多
#include<stdio.h>
#include<iostream>
using namespace std;
int main()
{
int n;
scanf("%d",&n);
int a,b;
string s;
while(n--)
{
cin>>a>>b>>s;
double t=0;
int flag=0;
for(int i=4;i<s.size();i++)
{
if(s[i]>='0'&&s[i]<='9'&&flag==0)
t=t*10.0+s[i]-'0';
else if(s[i]>='0'&&s[i]<='9'&&flag==1)
t=t+(s[i]-'0')/10.0;
else
flag=1;
}
if(s[3]=='-')
t=a*60+b-(t-8)*60;
else
t=a*60+b+(t-8)*60;
a=(int)(t/60)%24;
b=(int)t%60;
printf("%02d:%02d\n",a,b);
}
}