题目:上帝造题的七分钟
思路:
嗯听说是二维树状数组的区间修改+区间查询。
然后在洛谷不开O2 TLE ,开了O2 RE,且分数在55~100不等…
在joyoi过了的…
代码:
(交上去不一定能过)
#pragma GCC optimize(2)
#include<bits/stdc++.h>
using namespace std;
#define lowbit(x) (x&-x)
#define ll long long
#define db double
void readc(char& x) {
while(!isalpha(x)) x=getchar();
}
void read(int& x) {
scanf("%d",&x);
}
void writell(ll x) {
printf("%lld",x);
}
void write(int x) {
printf("%d",x);
}
void writen() {
printf("\n");
}
void writew() {
printf(" ");
}
#define maxn 2048
int n,m;
int a[maxn+2][maxn+2];
int ai[maxn+2][maxn+2];
int aj[maxn+2][maxn+2];
int aij[maxn+2][maxn+2];
void adda(int x,int y,int k) {
while(x<=n) {
int yy=y;
while(y<=m) {
a[x][y]+=k;
y+=lowbit(y);
}
x+=lowbit(x);
y=yy;
}
}
void addai(int x,int y,int k) {
while(x<=n) {
int yy=y;
while(y<=m) {
ai[x][y]+=k;
y+=lowbit(y);
}
x+=lowbit(x);
y=yy;
}
}
void addaj(int x,int y,int k) {
while(x<=n) {
int yy=y;
while(y<=m) {
aj[x][y]+=k;
y+=lowbit(y);
}
x+=lowbit(x);
y=yy;
}
}
void addaij(int x,int y,int k) {
while(x<=n) {
int yy=y;
while(y<=m) {
aij[x][y]+=k;
y+=lowbit(y);
}
x+=lowbit(x);
y=yy;
}
}
int suma(int x,int y) {
int s=0;
while(x>0) {
int yy=y;
while(y>0) {
s+=a[x][y];
y-=lowbit(y);
}
x-=lowbit(x);
y=yy;
}
return s;
}
int sumai(int x,int y) {
int s=0;
while(x>0) {
int yy=y;
while(y>0) {
s+=ai[x][y];
y-=lowbit(y);
}
x-=lowbit(x);
y=yy;
}
return s;
}
int sumaj(int x,int y) {
int s=0;
while(x>0) {
int yy=y;
while(y>0) {
s+=aj[x][y];
y-=lowbit(y);
}
x-=lowbit(x);
y=yy;
}
return s;
}
int sumaij(int x,int y) {
int s=0;
while(x>0) {
int yy=y;
while(y>0) {
s+=aij[x][y];
y-=lowbit(y);
}
x-=lowbit(x);
y=yy;
}
return s;
}
void Add(int x,int y,int k){
adda(x,y,k);addai(x,y,k*x);addaj(x,y,k*y);addaij(x,y,k*x*y);
}
int Sum(int x,int y){
return suma(x,y)*(x*y+x+y+1)-sumai(x,y)*(y+1)-sumaj(x,y)*(x+1)+sumaij(x,y);
}
int main() {
char opr;
readc(opr);read(n);read(m);
while(true) {
while(~scanf("%c",&opr)&&!isalpha(opr));
if(!isalpha(opr)) break;
if(opr=='L') {
int x,y,s,t,k;
read(x);read(y);read(s);read(t);read(k);
x++,y++,s++,t++;
Add(s+1,t+1,k);Add(s+1,y,-k);Add(x,t+1,-k);Add(x,y,k);
} else {
int x,y,s,t;
read(x);read(y);read(s);read(t);
x++,y++,s++,t++;
write(Sum(s,t)-Sum(s,y-1)-Sum(x-1,t)+Sum(x-1,y-1));writen();
}
}
return 0;
}