Problem Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
Sample Input
2 5 6 -1 5 4 -7 7 0 6 -1 1 -6 7 -5
Sample Output
Case 1: 14 1 4 Case 2: 7 1 6
Author
Ignatius.L
Recommend
#include <iostream>
using namespace std;
int main()
{
int a[100005],left,right,n,cnt=1,m,temp;
cin>>n;
while(n--)
{
left=right=temp=1;
int maxx=-1000;
int sum=0;
cin>>m;
for(int i=1;i<=m;i++)
{
cin>>a[i];
sum+=a[i];
if(sum>maxx)
{
maxx=sum;
left=temp;
right=i;
}
if(sum<0)
{
sum=0;
temp=i+1;
}
}
printf("Case %d:\n",cnt++);
printf("%d %d %d\n",maxx,left,right);
if(n>0) printf("\n");
}return 0;
}
right 记录 最大值时 的 终点下标(终点)
left是起点
如果和小于0,则从下一位重置起始值与和。
刚刚接触 动态规划。
Problem Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
Sample Input
2 5 6 -1 5 4 -7 7 0 6 -1 1 -6 7 -5
Sample Output
Case 1: 14 1 4 Case 2: 7 1 6
Author
Ignatius.L
Recommend