1012 The Best Rank (25分)

To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C - C Programming Language, M - Mathematics (Calculus or Linear Algrbra), and E - English. At the mean time, we encourage students by emphasizing on their best ranks – that is, among the four ranks with respect to the three courses and the average grade, we print the best rank for each student.
For example, The grades of C, M, E and A - Average of 4 students are given as the following:
StudentID C M E A
310101 　98 85 88 90
310102 　70 95 88 84
310103 　82 87 94 88
310104 　91 91 91 91
Then the best ranks for all the students are No.1 since the 1st one has done the best in C Programming Language, while the 2nd one in Mathematics, the 3rd one in English, and the last one in average.

Input Specification:

Each input file contains one test case. Each case starts with a line containing 2 numbers N and M (≤2000), which are the total number of students, and the number of students who would check their ranks, respectively. Then N lines follow, each contains a student ID which is a string of 6 digits, followed by the three integer grades (in the range of [0, 100]) of that student in the order of C, M and E. Then there are M lines, each containing a student ID.

Output Specification:

For each of the M students, print in one line the best rank for him/her, and the symbol of the corresponding rank, separated by a space.
The priorities of the ranking methods are ordered as A > C > M > E. Hence if there are two or more ways for a student to obtain the same best rank, output the one with the highest priority.
If a student is not on the grading list, simply output N/A.

按照不同的分数进行排序，分为四个序列，用map实现由id到rank的映射。对于四个分数的排序，不需要写四个cmp函数，只需要在cmp函数中用一个全局变量来控制按哪个分数排序即可。

#include<iostream>
#include<vector>
#include<unordered_map>
#include<algorithm>
using namespace std;
struct stu {
	string id;
	int score[4] = { 0 };
};
vector<stu>rec;//借助vector实现排序
unordered_map<string, int>refl[4];
char tag[4] = { 'A','C','M','E' };
int choice;
bool cmp(stu s1, stu s2) {
	return s1.score[choice] > s2.score[choice];
}
int main() {
	int n, m;
	cin >> n >> m;
	for (int i = 0; i < n; i++) {
		stu temp;
		cin >> temp.id >> temp.score[1] >> temp.score[2] >> temp.score[3];
		temp.score[0] = (temp.score[1] + temp.score[2] + temp.score[3]) / 3;
		rec.push_back(temp);
	}
	for (int i = 0; i < 4; i++) {
		choice = i;
		sort(rec.begin(), rec.end(), cmp);
		int preS = rec[0].score[i], rank, preR = 1;
		refl[i][rec[0].id] = 1;
		for (int j = 1; j < rec.size(); j++) {
			if (rec[j].score[i] == preS)rank = preR;
			else {
				rank = j + 1;
				preS = rec[j].score[i];
				preR = rank;
			}
			refl[i][rec[j].id] = rank;
		}
	}
	for (int i = 0; i < m; i++) {
		string id;
		cin >> id;
		if (refl[0].count(id) == 0) {
			cout << "N/A" << endl;
			continue;
		}
		int minR = refl[0][id], pos = 0;
		for (int j = 1; j < 4; j++) {
			if (refl[j][id] < minR) {
				pos = j;
				minR = refl[j][id];
			}
		}
		cout << refl[pos][id] << " " << tag[pos] << endl;
	}
	return 0;
}