[P1074]靶形数独

最新推荐文章于 2024-12-04 13:03:00 发布

原创最新推荐文章于 2024-12-04 13:03:00 发布 · 301 阅读

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原题链接

75分存档待改

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<queue>
#include<stdio.h>
using namespace std;

struct hehe
{
    int xp,yp;
}empt[100];


int sma[10][10],x[10][10],y[10][10],a[10][10],ans=-1,an,emp;
int q[10][10]=
{
    0,0,0,0,0,0,0,0,0,0,
    0,6,6,6,6,6,6,6,6,6,
    0,6,7,7,7,7,7,7,7,6,
    0,6,7,8,8,8,8,8,7,6,
    0,6,7,8,9,9,9,8,7,6,
    0,6,7,8,9,10,9,8,7,6,
    0,6,7,8,9,9,9,8,7,6,
    0,6,7,8,8,8,8,8,7,6,
    0,6,7,7,7,7,7,7,7,6,
    0,6,6,6,6,6,6,6,6,6,        
};


int h[10][10]=
{
    0,0,0,0,0,0,0,0,0,0,
    0,1,1,1,2,2,2,3,3,3,
    0,1,1,1,2,2,2,3,3,3,
    0,1,1,1,2,2,2,3,3,3,
    0,4,4,4,5,5,5,6,6,6,
    0,4,4,4,5,5,5,6,6,6,
    0,4,4,4,5,5,5,6,6,6,
    0,7,7,7,8,8,8,9,9,9,
    0,7,7,7,8,8,8,9,9,9,
    0,7,7,7,8,8,8,9,9,9,
};

void dfs(int maki,int tot)
{   
    int k;
    int nx=empt[tot].xp,ny=empt[tot].yp;
    if(tot==emp+1)
    {
        ans=max(ans,maki);
        return;
    }

    for(k=1;k<=9;k++)
        if((x[nx][k]==0)&&(y[ny][k]==0)&&(sma[h[nx][ny]][k]==0))
        {
            a[nx][ny]=k;
            x[nx][k]=1;
            y[ny][k]=1;
            sma[h[nx][ny]][k]=1;
            tot++;
            dfs(maki+k*q[nx][ny],tot);
            a[nx][ny]=0;
            x[nx][k]=0;
            y[ny][k]=0;
            sma[h[nx][ny]][k]=0;    
            tot--;                  
        }           

}

int main()
{
    int i,j;

    for(i=1;i<=9;i++)
        for(j=1;j<=9;j++)
        {
            scanf("%d",&a[i][j]);
            if(a[i][j]!=0)
            {
                x[i][a[i][j]]=1;
                y[j][a[i][j]]=1;
                sma[h[i][j]][a[i][j]]=1;
                an+=a[i][j]*q[i][j];
            }   

            else 
            {
                emp++;  
                empt[emp].xp=i;
                empt[emp].yp=j; 
            }   
        }

    dfs(an,1);
    printf("%d",ans);

    return 0;
}

修改后已AC
AC代码

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<queue>
#include<stdio.h>
using namespace std;

int sma[10][10],x[10][10],y[10][10],a[10][10],can[10][10],ans=-1,emp;

int q[10][10]=
{
    0,0,0,0,0,0,0,0,0,0,
    0,6,6,6,6,6,6,6,6,6,
    0,6,7,7,7,7,7,7,7,6,
    0,6,7,8,8,8,8,8,7,6,
    0,6,7,8,9,9,9,8,7,6,
    0,6,7,8,9,10,9,8,7,6,
    0,6,7,8,9,9,9,8,7,6,
    0,6,7,8,8,8,8,8,7,6,
    0,6,7,7,7,7,7,7,7,6,
    0,6,6,6,6,6,6,6,6,6,        
};


int h[10][10]=
{
    0,0,0,0,0,0,0,0,0,0,
    0,1,1,1,2,2,2,3,3,3,
    0,1,1,1,2,2,2,3,3,3,
    0,1,1,1,2,2,2,3,3,3,
    0,4,4,4,5,5,5,6,6,6,
    0,4,4,4,5,5,5,6,6,6,
    0,4,4,4,5,5,5,6,6,6,
    0,7,7,7,8,8,8,9,9,9,
    0,7,7,7,8,8,8,9,9,9,
    0,7,7,7,8,8,8,9,9,9,
};

void dfs(int tot)
{   
    int i,j,k,nx,ny,sum=0,mi=99999999;

    if(tot>emp)
    {
        for(i=1;i<=9;i++)
            for(j=1;j<=9;j++)
                if(a[i][j]==0) return;
                else sum+=a[i][j]*q[i][j];

        ans=max(ans,sum);
    }

    memset(can,0,sizeof(can));
    for(i=1;i<=9;i++)
        for(j=1;j<=9;j++)
            if(!a[i][j])
            {
                for(k=1;k<=9;k++)
                    if((!x[i][k])&&(!y[j][k])&&(!sma[h[i][j]][k])) can[i][j]++;

                if(can[i][j]<mi)
                {
                    mi=can[i][j];   
                    nx=i;
                    ny=j;
                }

                if(mi==1) break;
            }

    if(mi==0) return;   
    if(mi==99999999)
    {
        int ma=0;
        for(i=1;i<=9;i++)
            for(j=1;j<=9;j++)
                if(a[i][j]==0) return;
                else ma+=a[i][j]*q[i][j];

        ans=max(ma,ans);
        return;
    }


    for(k=1;k<=9;k++)
        if((!x[nx][k])&&(!y[ny][k])&&(!sma[h[nx][ny]][k]))
        {
            a[nx][ny]=k;
            x[nx][k]=1;
            y[ny][k]=1;
            sma[h[nx][ny]][k]=1;

            dfs(tot+1);

            a[nx][ny]=0;
            x[nx][k]=0;
            y[ny][k]=0;
            sma[h[nx][ny]][k]=0;                        
        }           

}

int main()
{
    int i,j;

    for(i=1;i<=9;i++)
        for(j=1;j<=9;j++)
        {
            scanf("%d",&a[i][j]);

            if(a[i][j]!=0)
            {
                x[i][a[i][j]]=1;
                y[j][a[i][j]]=1;
                sma[h[i][j]][a[i][j]]=1;
            }   

            else emp++; 
        }

    dfs(1);

    printf("%d",ans);

    return 0;
}