qq_22774445的博客

由于S-R/S'-R'锁存器在所有时间内对输入都是敏感的，我们期望有一种器件，它只有在使能输入C有效时，才对输入敏感，具有使能端的S-R锁存器(S-R latch with enable)应运而生。总之，作者认为，只要掌握了S-R锁存器，S'-R'锁存器只不过是将输入信号进行反转，我们通过相应的分析即可得出S'-R'锁存器的输出。总结，本次我们介绍了S-R锁存器，S'-R'锁存器，具有使能端的S'-R'锁存器，D锁存器。①S,R均为0，S-R锁存器相当于双稳态元件，通过反馈回路维持电路之前的状态。...

串行全加器是上面这样，但是这种结构的缺点是，必须要等到上一片的结果算出来之后下一片才能进行工作，当级数很高的时候计算的时间将是每一片时间的n倍，会出现组合逻辑延时过长的问题。此时另一种进位方法——超前进位加法器就可以解决这一延时过高的问题。这里实在看不懂可以翻一番数电的超前进位加法器的内容。超前进位加法器就是用电路的复杂度来换时间。3.4位串行加法器（全加器）verilog代码如下：0。1.2输入1bit半加器。2.2输入1bit全加器。4.4位超前进位加法器。...

设计一个0～9的计数器，共10个周期。该计数器采用同步复位且复位为0。但是本题是希望该计数器并不是随着clk的变化而递增，而是随着一个slowena使能信号来控制增加。

还是1～10的计数器，唯一不同是同步复位为1.

代码】【HDLBits刷题】Count10..

设计一个4bit的计数器，从0～15，共16个周期。reset是同步复位且复位为0。

You're familiar with flip-flops that are triggered on the positive edge of the clock, or negative edge of the clock. A dual-edge triggered flip-flop is triggered on both edges of the clock. However, FPGAs don't have dual-edge triggered flip-flops, and alwa

For each bit in a 32-bit vector, capture when the input signal changes from 1 in one clock cycle to 0 the next. "Capture" means that the output will remain 1 until the register is reset (synchronous reset).Each output bit behaves like a SR flip-flop: The o

For each bit in an 8-bit vector, detect when the input signal changes from one clock cycle to the next (detect any edge). The output bit should be set the cycle after a 0 to 1 transition occurs.Here are some examples. For clarity, in[1] and anyedge[1] are

For each bit in an 8-bit vector, detect when the input signal changes from 0 in one clock cycle to 1 the next (similar to positive edge detection). The output bit should be set the cycle after a 0 to 1 transition occurs.Here are some examples. For clarity,

A JK flip-flop has the below truth table. Implement a JK flip-flop with only a D-type flip-flop and gates. Note: Qold is the output of the D flip-flop before the positive clock edge.module top_module ( input clk, input j, input k, output Q

我们在数字电路中经常使用到D触发器，有时候还会听到D锁存器这种电路，那么这两种电路到底有什么关系？又存在什么区别？方法一：功能的文字叙述　　1）D锁存器：　　　　功能分析文字描述：C = 0时，输出状态保持不变；C = 1时，输出随输入状态而改变。　　2）D触发器：　　　　功能分析文字描述： CLK=0时，主锁存器工作，接收输入信号Qm = D；从锁存器不工作，输出 Q 保持不变。　　CLK=1时，主锁存器不工作，Qm保持不变；从锁存器工作，将Qm传送到输出端。　

Implement the following circuit:Note that this is a latch, so a Quartus warning about having inferred a latch is expected.做一个D触发器module top_module ( input d, input ena, output q); always @(*)begin if(ena) q = d

Create 16 D flip-flops. It's sometimes useful to only modify parts of a group of flip-flops. The byte-enable inputs control whether each byte of the 16 registers should be written to on that cycle. byteena[1] controls the upper byte d[15:8], while byteena[

Create 8 D flip-flops with active high asynchronous reset. All DFFs should be triggered by the positive edge of clk.要求创建一个异步清零端的D触发器module top_module ( input clk, input areset, // active high asynchronous reset input [7:0] d, output

Create 8 D flip-flops with active high synchronous reset. The flip-flops must be reset to 0x34 rather than zero. All DFFs should be triggered by the negative edge of clk.实现具有高电平同步复位的8个D触发器，同时复位值为0x34，下降沿触发。module top_module ( input clk, input

Create 8 D flip-flops with active high synchronous reset. All DFFs should be triggered by the positive edge of clk.写一个带reset高电平有效复位的D触发器（时钟是上升沿触发）另外最好把在过程语句中的变量设置成reg格式，比如此处的q。（赋值语句左边的）module top_module ( input clk, input reset, /

Create 8 D flip-flops. All DFFs should be triggered by the positive edge ofclk.module top_module ( input clk, input [7:0] d, output [7:0] q); always @(posedge clk) q <= d;endmodule

A D flip-flop is a circuit that stores a bit and is updated periodically, at the (usually) positive edge of a clock signal.D flip-flops are created by the logic synthesizer when aclocked always blockis used (Seealwaysblock2). A D flip-flop is the si...

https://blog.youkuaiyun.com/qq_45838676/article/details/106146093