题目:输入一个字符串,输出该字符串中对称的子字符串的最大长度。
比如输入字符串“google”,由于该字符串里最长的对称子字符串是“goog”,因此输出4。
目前没想到更好的方法,时间复杂度是O(n^2);
int max_len(char* str)
{
char *p = str;
int len = 1 ;
while(*p != '\0')
{
char *first,*last;
first = p - 1;
last = p + 1;
while( first >= str && *last != '\0' && *first == *last)
{
first--;
last++;
}
if( (last - first - 1 ) > len)
len = last - first - 1;
first = p;
last = p + 1;
while( first >= str && *last != '\0' && *first == *last)
{
first--;
last++;
}
if( (last - first - 1 ) > len)
len = last - first - 1;
p++;
}
return len;
}