ny 217 a letter and a number

#include<stdio.h>
int main()
{
    int t,m;
    char a;
    while(scanf("%d",&t)!=EOF)
    {
    getchar();
    while(t--)
    {
    scanf("%c%d",&a,&m);
    if(a<'a')
    printf("%d\n",a+m-64);
    else
    printf("%d\n",96+m-a);
    getchar();
}
                               }
return 0;   
} 

a letter and a number

时间限制：3000 ms  |  内存限制：65535 KB

难度：1

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4