lc311309010103的专栏

A+B for Input-Output Practice (II) Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 59745    Accepted Submission(s): 39408 Problem Desc

#include int main() {     int a,b;     while(scanf("%d%d",&a,&b)!=EOF)     {      printf("%d\n",a+b);                                    } return 0;    }

杨辉三角 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 35208    Accepted Submission(s): 14695 Problem Description 还记得中学时候学过的杨辉三角吗？具体的定义这里

#include int main() {     int t,n,i,s;     while(scanf("%d",&t)!=EOF&&(t!=0))     {       s=0;      for(i=0;i      {       scanf("%d",&n);       s+=n;                      }      printf("

#include main() {       int m,n,i,sum;       sum=0;       while(scanf("%d\n",&m)!=EOF)       {       while(m--)       {                 scanf("%d",&n);                 while(n--)          

#include main() { int m,n,sum; sum=0; while(scanf("%d%d",&m,&n)!=EOF) {   sum=m+n;   printf("%d\n\n",sum);   sum=0; }   return 0;        }

#include main() {       int m,n,sum;       sum=0;       while(scanf("%d",&m)&&(m!=0))       {         while(m--)         {         scanf("%d",&n);         sum+=n;         }         printf(

新生晚会 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8306    Accepted Submission(s): 2947 Problem Description 开学了，杭电又迎来了好多新生。ACMer想为新

#include int main() {    int n,i,sum=0;    while(scanf("%d",&n)!=EOF)    {      for(i=1;i      sum+=i;      printf("%d\n\n",sum);      sum=0;                              }       return 0;