import heapq
# 第一种
"""
函数定义:
heapq.heappush(heap, item)
- Push the value item onto the heap, maintaining the heap invariant.
heapq.heappop(heap)
- Pop and return the smallest item from the heap, maintaining the heap invariant.
If the heap is empty, IndexError is raised. To access the smallest item without popping it, use heap[0].
"""
nums = [2, 3, 5, 1, 54, 23, 132]
heap = []
for num in nums:
heapq.heappush(heap, num) # 加入堆
print(heap)
print(heap[0]) # 如果只是想获取最小值而不是弹出,使用heap[0]
print([heapq.heappop(heap) for _ in range(len(nums))]) # 堆排序结果
# out: [1, 2, 3, 5, 23, 54, 132]
# 第二种
nums = [2, 3, 5, 1, 54, 23, 132]
heapq.heapify(nums)
print([heapq.heappop(nums) for _ in range(len(nums))]) # 堆排序结果
# out: [1, 2, 3, 5, 23, 54, 132]
【Python】heapq模块
最新推荐文章于 2025-04-18 13:44:20 发布