HDOJ 1019 Least Common Multiple

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 20538    Accepted Submission(s): 7660

Problem Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

 

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

 

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

 

Sample Input

  
  

   
   2
3 5 7 15
6 4 10296 936 1287 792 1
  
  

 

Sample Output

  
  

   
   105
10296
  
  

 

Source

East Central North America 2003, Practice

 

Recommend

JGShining

 

求n个数的最小公倍数，就是先求前两个，用结果和第三个求最小公倍数。。。以此类推

#include <iostream>
using namespace std;
int gcd(int,int);
int main(int argc, char *argv[])
{
	int a,n,m; long long s;
	cin>>m;
	for (int i=1;i<=m;++i){
		cin>>n; s=1;
		for(int j=1;j<=n;++j){
			cin>>a;
			s=s*a/gcd(s,a);
		}
		cout<<s<<endl;
	} 
	return 0;
}

int gcd(int a,int b){
	return b?gcd(b,a%b):a;
}

kdwycz的网站：  http://kdwycz.com/

kdwyz的刷题空间：http://blog.youkuaiyun.com/kdwycz