python numpy 统计数组中某一元素出现次数函数

import numpy as np


def np_count(nparray, x):
    i = 0
    for n in nparray:
        if n == x:
            i += 1
    return i


arr = np.array([2, 3, 3, 1, 2, 2])
print(np_count(arr, 2))

output： 3

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import numpy as np
from collections import Counter

arr = np.array([2, 3, 3, 1, 2, 2])
print(Counter(arr)[2])