PAT甲级 -- 1005 Spell It Right (20 分)

最新推荐文章于 2024-12-18 16:22:07 发布

名字被猪吃掉了

最新推荐文章于 2024-12-18 16:22:07 发布

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博客要求对给定的非负整数N，计算其各位数字之和，并将和的每一位用英文输出。给出了输入、输出规格，还提及注意字符与数字的转换方法，如字符转数字用 -‘0’ ，数字转字符用 +‘0’。

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Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (≤10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output:

one five

#include <iostream>
#include <cstring>
using namespace std;

char num[10][15] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
char cc[200], nn[200];
int sum = 0;
int ct = 0;

int main()
{
    scanf("%s", cc);
    int len = strlen(cc);  //字符串长度
    for(int i = 0; i < len; i++)
    {
        sum += cc[i]-'0';  //转数字
    }
    if(sum == 0) printf("%s", num[0]);
    while(sum != 0)
    {
        nn[ct++] = (sum%10) + '0';
        sum /= 10;
    }
    for(int i = ct - 1; i >= 0; i--)
    {
        if(i!=0)
            printf("%s ",num[nn[i]-'0']);
        else
            printf("%s",num[nn[i]-'0']);
    }

    return 0;
}

注意点：

1.字符转数字 -‘0’ ，数字转字符 +‘0’