Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
Example:
Input: The root of a Binary Search Tree like this: 5 / \ 2 13 Output: The root of a Greater Tree like this: 18 / \ 20 13
搜索二叉树的遍历。
求所有大于当前节点值的所有数之和,并将其作为该节点新的值。程序如下所示:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
private int sum = 0;
public TreeNode convertBST(TreeNode root) {
if (root == null){
return root;
}
root.right = convertBST(root.right);
sum += root.val;
root.val = sum;
root.left = convertBST(root.left);
return root;
}
}