75. Sort Colors
Medium
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Given an array with n objects colored red, white or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white and blue.
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.
Note: You are not suppose to use the library's sort function for this problem.
Example:
Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Follow up:
- A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. - Could you come up with a one-pass algorithm using only constant space?
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Submissions
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第一次用的冒泡排序,结果也还可以,第二次参考别人的代码如下
class Solution {
public:
void sortColors(vector<int>& nums) {
int left=0,right=nums.size()-1,i=0;//0都保存在left,2都保存在right
while(i<=right){
if(nums[i]==0){
swap(nums[left],nums[i]);
left++;i++;
}else if(nums[i]==1){
i++;
}else{
swap(nums[right],nums[i]);
right--;
}
}
}
};
class Solution {
public:
void sortColors(vector<int>& nums) {//冒泡
for(int i=0;i<nums.size();i++){
for(int j=i+1;j<nums.size();j++){
if(nums[i]>nums[j]) swap(nums[i],nums[j]);
}
}
}
};