numpy 矩阵的简单运算

import numpy as np

a = np.array([10, 20, 30, 40])
b = np.arange(4)

c = a - b
print(a)
print(b)
print(c)
print('************************')
d = b**2
print(b)
print(d)
print('************************')
e = 10 * np.sin(a)
print(a)
print(e)
print('************************')
print(b)
print(b < 3)