给出一个整数N,将N表示为2个整数i j的平方和(i <= j),如果有多种表示,按照i的递增序输出。
例如:N = 130,130 = 3^2 + 11^2 = 7^2 + 9^2 (注:3 11同11 3算1种)
#include <iostream>
#include <math.h>
using namespace std;
int input[40000];
int main()
{
int N;
cin >> N;
int maxVal = sqrt(N);
for (int i = 0; i <= maxVal; i++)
{
input[i] = i*i;
}
int left = 0;
int right = maxVal;
bool found = false;
while (left <= right)
{
int temp = input[left] + input[right];
if (temp == N)
{
cout << left << " " << right << endl;
found = true;
left++;
}
else if (temp > N)
{
right--;
}
else
{
left++;
}
}
if (!found)
{
cout << "No Solution" << endl;
}
return 0;
}