VS2012 Error:不存在从“——”到“——*”的适当转换函数—已解决

最新推荐文章于 2025-05-04 23:57:55 发布

原创最新推荐文章于 2025-05-04 23:57:55 发布 · 2.6w 阅读

5 ·

CC 4.0 BY-SA版权

VS2012 专栏收录该内容

7 篇文章

订阅专栏

这篇博客讲述了在使用VS2012进行C语言编程时遇到的一个错误，涉及链表结构的创建和打印。在创建和打印链表的函数中，由于指针使用不当导致编译错误。通过修改函数参数，将`void print(struct Student head)`更改为`void print(struct Student *head)`，成功解决了问题。

源代码功能为建立并输出链表。《C程序设计》P316。

源代码如下：

#include<stdio.h>
#include<malloc.h>
#define LEN sizeof(struct Student)
struct Student
{
long num;
float score;
struct Student* next;
};
int n;
struct Student* creat()
{
struct Student* head;
struct Student* p1,*p2;
n = 0;
p1 = p2 =(struct Student*)malloc(LEN);
scanf_s("%ld,%f",&p1->num,&p1->score);
head = NULL;
while (p1 -> num!= 0)
{
n = n + 1;
if(n == 1)head = p1;
else p2 -> next = p1;
p2 = p1;
p1 = (struct Student*)malloc(LEN);
scanf_s("%ld,%f",&p1 -> num,&p1 -> score);
}
p2 -> next = NULL;
return(head);
};
void print(struct Student head )
{
struct Student* p;
printf("\nNow,These %d records are:\n",n);
p = head;
if(head != NULL)
do
{
printf("%ld %5.1f\n",p->num,p->score);
p = p->next;
} while (p != NULL);
}
void main()
{
struct Student* head;
head = creat();
print(head);
}