1058. A+B in Hogwarts (20)
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:3.2.1 10.16.27Sample Output:
14.1.28
题意:给你两个数,每个数由三个数组成,第三个数是29进制,第二个数是17进制,求出他们的和
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <cmath>
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <vector>
#include <bitset>
using namespace std;
#define LL long long
const int INF = 0x3f3f3f3f;
int main()
{
int a1,b1,c1,a2,b2,c2,a3,b3,c3 ;
while (~scanf("%d.%d.%d", &a1, &b1, &c1))
{
scanf("%d.%d.%d", &a2, &b2, &c2);
int cnt = (c1 + c2) / 29;
c3 = (c1 + c2) % 29;
b3 = (b1 + b2 + cnt) % 17;
cnt = (b1 + b2 + cnt) / 17;
a3 = a1 + a2 + cnt;
printf("%d.%d.%d\n", a3, b3, c3);
}
return 0;
}