Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
The number of elements initialized in nums1 and nums2 are m and n respectively.
翻译:给定两个排好序的数组,数组的长度给定,合并两个数组,并保持数组的原来的顺序。
分析:可以从num2中每次取出一个给num1做比较,插入。但是其实不如先整体插入,然后再排序。
class Solution{
public:
void merge(vector<int>&num1,int m,vector<int>& num2,int n)
{
int c;
for(int i=0;i<n;i++)
num1.push_back(num2[i]);
for(int i=0;i<n+m-1;i++){
for(int j=i+1;j<m+n;j++)
if(num1[i]>num1[j])
{
c=num1[i];
num1[i]=num1[j];
num1[j]=c;
}
}
}
};
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