53. Maximum Subarray My Submissions QuestionEditorial Solution

最新推荐文章于 2024-01-21 00:18:48 发布

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#intresting DP #need another try

本文介绍了一种寻找具有最大和的连续子数组的算法。通过动态规划方法解决此问题，并给出了具体的实现代码示例。

Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.

找最大，最小值就要考虑 DP

class Solution {
public:
    int maxSubArray(vector<int>& nums) {
        if( nums.empty()) return 0;
        
        int localMax = nums[0], globalMax = nums[0];
        for( int i = 1; i < nums.size(); i++) {
            localMax = max(localMax + nums[i], nums[i]);
            globalMax = max(globalMax, localMax);
        }
        return globalMax;
    }
};