【HDU】 2602 Bone Collector

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 43693    Accepted Submission(s): 18229

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2 ³¹).

 

Sample Input

  
  

   
   1
5 10
1 2 3 4 5
5 4 3 2 1
  
  

 

Sample Output

14

题解：01背包的裸题。

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>

using namespace std;

int n,v,T,c[1005],val[1005],d[1005];

int main()
{
    scanf("%d",&T);
    while (T--)
    {
        memset(d,0,sizeof(d));
        scanf("%d%d",&n,&v);
        for (int i=1;i<=n;i++) scanf("%d",&val[i]);
        for (int i=1;i<=n;i++) scanf("%d",&c[i]);
        for (int i=1;i<=n;i++)
            for (int j=v;j>=c[i];j--)
            d[j]=max(d[j],d[j-c[i]]+val[i]);
        printf("%d\n",d[v]);
    }
    return 0;
}