39.平衡二叉树

题目描述

         输入一棵二叉树，判断该二叉树是否是平衡二叉树。

解题思路

         平衡二叉树的左右子树的高度差最多是1；

    private class TreeNode {
        int val = 0;
        TreeNode left = null;
        TreeNode right = null;

        public TreeNode(int val) {
            this.val = val;

        }
    }

    private int getTreeDepth(TreeNode root) {
        if (root == null) {
            return 0;
        }

        int left = getTreeDepth(root.left);
        if (left == -1) {
            return -1;
        }
        int right = getTreeDepth(root.right);
        if (right == -1) {
            return -1;
        }

        return Math.abs(left - right) > 1 ? -1 : 1 + Math.max(getTreeDepth(root.left), getTreeDepth(root.right));
    }

    public boolean IsBalanced_Solution(TreeNode root) {
        return getTreeDepth(root) != -1;
    }