数学建模4.4

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#数学建模

 
MAX_A = 15 
MAX_B = 24  
MAX_DEBUG = 5 
  
 
products = [  
    {"name": "Ⅰ", "A_hours": 1, "B_hours": 6, "debug_hours": 1, "profit": 2},  # 假设产品Ⅰ至少使用1小时设备A  
    {"name": "Ⅱ", "A_hours": 5, "B_hours": 2, "debug_hours": 1, "profit": 1}  
]  
  
 
max_profit = 0  
best_plan = {}  
  
 
for i in range(MAX_A // products[0]["A_hours"] + 1):  
    for j in range(MAX_B // products[1]["B_hours"] + 1):  
        # 计算调试时间是否足够  
        if (i + j) * max(products[0]["debug_hours"], products[1]["debug_hours"]) > MAX_DEBUG:  
            continue   
  
 
        total_A_hours = i * products[0]["A_hours"] + j * products[1]["A_hours"]  
        total_B_hours = i * products[0]["B_hours"] + j * products[1]["B_hours"]  
  
 
        if total_A_hours > MAX_A or total_B_hours > MAX_B:  
            continue  
  
 
        total_profit = i * products[0]["profit"] + j * products[1]["profit"]  
  
 
        if total_profit > max_profit:  
            max_profit = total_profit  
            best_plan = {"Ⅰ": i, "Ⅱ": j}  
  
 
print(f"最优生产计划：产品Ⅰ生产{best_plan['Ⅰ']}件，产品Ⅱ生产{best_plan['Ⅱ']}件")  
print(f"最大利润为：{max_profit}元")