Codeforces Round #508 (Div. 2) B. Non-Coprime Partition

CodeForces CF #508 Div.2 A. Equality http://codeforces.com/contest/1038/problem/A hash,min,没有其他内容了,滴,签到完成 B. Non-Coprime Partition http://codeforces.com/contest/1038/problem/B 给你一个数n,希望你把它分成两组,满足两组数各自的和的GCD>1。 先看数据规模... 阅读详情
  1. problem link:http://codeforces.com/contest/1038/problem/B
  2. 题意:给你一个n,让你将从1~n这n个数分为两部分,使得两部分的和的最大公约数不为1。观察发现,只要把前n-1个数分成一个组,然后n分成一个组,然后n==1和n==2的情况特殊处理就好了。
    证明一下这个为什么是正确的:
    当n>=3时
    前n-1个数的和为(n-1)*n/2
    而n的和为n。
    则观察发现当n>=3时,其两个值一定有大于1的最大公约数。

  3. AC code:

#include<iostream>
using namespace std;
const int N=4503;
int main(){
    ios::sync_with_stdio(false);cin.tie(0);
    int n;cin>>n;
    if(n==1||n==2)cout<<"No"<<endl;
    else {
        cout<<"Yes"<<endl;
        cout<<n-1<<" ";
        for(int i=1;i<=n-1;i++)cout<<i<<" ";
        cout<<endl;cout<<1<<" "<<n<<endl;
    } 
}
python调用海康工业相机并用opencv显示(整体实现) python语言调用海康机器人(hikrobotics)工业相机 第一章 Python 语言下连接海康工业相机,并获取数据 文章目录 系列文章目录 前言 目录 python语言调用海康机器人(hikrobotics)工业相机 文章目录 前言 一、底层接口的准备 二、使用步骤 1.引入库 2.枚举设备 3.判断设备类型 4.输入连接设备 5.创建相机实例并创建句柄 6.打开设备 7.获取相关参数 8.主动获取图像 9.开启取流并获取每张. 阅读详情

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Light2Chasers的博客 526

Codeforces Round #507 (Div. 2, based on Olympiad of Metropolises) B. Shashlik Cooking

problem link:http://codeforces.com/contest/1040/problem/B 题意:给你一个n代表有n个初始状态为正面的羊肉串,k代表你每次可以随机选择一个数值i,并把第 i-k 到第 i+k 个羊肉串翻过来。问你最少需要多少次可以把所有羊肉串全部翻过来。 解题报告:经过观察发现,当k==0时,那就需要翻n次了,当n&lt;=(2*k)+1时,肯定翻中间那个...

Light2Chasers的博客 525
上一篇: Codeforces Round #508 (Div. 2) A. Equality
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