class Solution {
public:
int dfs(int left, int right) {
int sub_Cnt = 0;
if (left > right)return sub_Cnt;
for (int i = left; i <= right; ++i) {
int LeftTree_Cnt = dfs(left, i - 1);
int RightTree_Cnt = dfs(i + 1, right);
sub_Cnt += LeftTree_Cnt*RightTree_Cnt;
}
return sub_Cnt;
}
int numTrees(int n) {
if (n == 0)return 0;
return dfs(1,n);
}
};
96. Unique Binary Search Trees
最新推荐文章于 2021-05-17 12:15:23 发布
