题目描述:
Given an array nums
, write a function to move all 0
's to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12]
, after calling your function, nums
should be [1, 3, 12, 0, 0]
.
Note:
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
定义两个指针,i每次移动一步,j每次都向后遍历,直到指向非0的数,那么这两个指针交换。在j>i时,nums[i]必定为0,因为非0的数都被j遍历过,所以两个指针交换可以令所有的0逐渐移到数组后面。
class Solution {
public:
void moveZeroes(vector<int>& nums) {
int i=0;
int j=0;
while(i<nums.size())
{
if(nums[i]==0) i++;
else
{
swap(nums[i],nums[j]);
i++;
j++;
}
}
}
};