题目描述:
You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.
Write a function to determine if the starting player can guarantee a win.
Example:
Input: s = "++++" Output: true Explanation: The starting player can guarantee a win by flipping the middle "++" to become "+--+".
Follow up:
Derive your algorithm's runtime complexity.
class Solution {
public:
bool canWin(string s) {
for (int i=1;i<s.size();i++)
{
if (s[i]=='+'&&s[i-1]=='+'&&!canWin(s.substr(0,i-1)+"--"+s.substr(i+1)))
return true;
}
return false;
}
};
本文深入解析了一种名为FlipGame的策略游戏,玩家需将++翻转为--来获胜。通过递归算法判断首玩家是否能确保胜利,并探讨了算法的时间复杂度。
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