PTA 乙级 1034 有理数四则运算

最新推荐文章于 2024-09-27 01:00:00 发布

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最新推荐文章于 2024-09-27 01:00:00 发布

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分类专栏： PTA Basic Level Practice 文章标签： C

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本文介绍了一个用于进行分数加减乘除运算的C语言程序。该程序通过定义gg函数计算两个数的最大公约数，并使用printk函数打印分数的运算结果。程序能够处理包括负数在内的各种分数运算场景，实现了分数的简化输出。

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代码实现：

#include<stdio.h>  

long gg(long x, long y)
{
	return y == 0 ? x : gg(y, x%y);
}

void printk(long a, long b)
{
	int flag = 0;
	long gf = gg((long)fabs(a), (long)fabs(b));

	if (a == 0)
	{
		printf("0"); return;
	}
	if (a < 0)
	{
		printf("(-");
		a = (-1)*a;
		flag = 1;
	}
	if (a == b)printf("1");
	else if (a > b)
	{
		a = a / gf;
		b = b / gf;
		if (a%b != 0)	printf("%ld %ld/%ld", a / b, a%b, b);
		else printf("%ld", a / b);
	}
	else
	{
		a = a / gf;
		b = b / gf;
		printf("%ld/%ld", a, b);
	}
	if (flag == 1)printf(")");
}

int main(void)
{
	long a1 = 0, b1 = 0, a2 = 0, b2 = 0;
	long n = 0, d = 0;

	scanf("%ld/%ld %ld/%ld", &a1, &b1, &a2, &b2);
	n = a1 * b2 + a2 * b1;d = b1 * b2;
	printk(a1, b1);printf(" + ");printk(a2, b2);printf(" = ");printk(n, d);printf("\n");
	n = a1 * b2 - a2 * b1;d = b1 * b2;
	printk(a1, b1);printf(" - ");printk(a2, b2);printf(" = ");printk(n, d);printf("\n");
	n = a1 * a2;d = b1 * b2;
	printk(a1, b1);printf(" * ");printk(a2, b2);printf(" = ");printk(n, d);printf("\n");
	n = a1 * b2;d = b1 * a2;
	printk(a1, b1);printf(" / ");printk(a2, b2);printf(" = ");
	if (d == 0)printf("Inf\n");
	else
	{
		if (d < 0)
		{
			n = -n;
			d = -d;
		}
		printk(n, d);printf("\n");
	}

	return 0;

}