UVA_10405 Longest Common Subsequence(DP)

最新推荐文章于 2016-03-10 17:11:15 发布

EaShion1994

最新推荐文章于 2016-03-10 17:11:15 发布

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Longest Common Subsequence

Given two sequences of characters, print the length of the longest common subsequence of both sequences. For example, the longest common subsequence of the following two sequences:

abcdgh
aedfhr

is adh of length 3.

Input consists of pairs of lines. The first line of a pair contains the first string and the second line contains the second string. Each string is on a separate line and consists of at most 1,000 characters

For each subsequent pair of input lines, output a line containing one integer number which satisfies the criteria stated above.

Sample input

a1b2c3d4e
zz1yy2xx3ww4vv
abcdgh
aedfhr
abcdefghijklmnopqrstuvwxyz
a0b0c0d0e0f0g0h0i0j0k0l0m0n0o0p0q0r0s0t0u0v0w0x0y0z0
abcdefghijklmnzyxwvutsrqpo
opqrstuvwxyzabcdefghijklmn

Output for the sample input

题意：给出两字符串(可能含有空格)，求出两字符串最长的公共子串。

题解：DP，原理很清楚，写出递归式，注意输入可能含有空格。

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <cstring>
#define MAX_N 1005

using namespace std;

int n,m;
char s[MAX_N],t[MAX_N];
int dp[MAX_N][MAX_N];
int main()
{
    while( gets(s) && gets(t)  )
    {
        n = strlen(s);
        m = strlen(t);
        for( int i = 0; i < n; i++ )
        {
            for( int j = 0; j < m; j++ )
            {
                if( s[i] == t[j] )
                    dp[i+1][j+1] = dp[i][j] + 1;
                else
                    dp[i+1][j+1] = max(dp[i][j+1],dp[i+1][j]);
            }
        }
        cout<<dp[n][m]<<endl;
    }
    return 0;
}