蓝桥杯数码管静态显示

分为段码（a,b,c,d,e,f,g,dp)和公共端

 

可理解为P0口直接控制这个端口了

 

公共端由Y6控制 。

Y7控制段码，Y6控制公共端

 

例题：让第一个数码管显示数字6

#include "reg52.h"

unsigned char code SMDD_duanma[18]={0xc0,0xf9,0xa4,0xb0,

                               0x99,0x92,0x82,0xf8,

                             0x80,0x90,0x88,0x80,

                               0xc6,0xc0,0x86,0x8e,

                               0xbf,0x7f};

void HC138init(unsigned char i)

{

switch(i)

{

case 4:

P2=(P2&0x1f)|0x80;

break;

case 5:

P2=(P2&0x1f)|0xa0;

break;

case 6:

P2=(P2&0x1f)|0xc0;

break;

case 7:

P2=(P2&0x1f)|0xe0;

break;

}

}

void ShowSMG()

{

HC138init(6);

P0=0x01;

HC138init(7);

P0=0x82;

}

void main()

{

ShowSMG();

while(1)

{

}

}

所有数码管循环播放6

#include "reg52.h"

unsigned char code SMDD_duanma[18]={0xc0,0xf9,0xa4,0xb0,

                               0x99,0x92,0x82,0xf8,

                             0x80,0x90,0x88,0x80,

                               0xc6,0xc0,0x86,0x8e,

                               0xbf,0x7f};

void delay(unsigned int t)

{

while(t--);

while(t--);

}

void HC138init(unsigned char i)

{

switch(i)

{

case 4:

P2=(P2&0x1f)|0x80;

break;

case 5:

P2=(P2&0x1f)|0xa0;

break;

case 6:

P2=(P2&0x1f)|0xc0;

break;

case 7:

P2=(P2&0x1f)|0xe0;

break;

}

}

void ShowSMG_Bit(unsigned char dat,unsigned char pos)

{

HC138init(6);

P0=0x01<<pos;

HC138init(7);

P0=dat;

}

void SMG_Static()

{

unsigned char i;

for(i=0;i<8;i++)

{

ShowSMG_Bit(SMDD_duanma[6],i);

delay(60000);

}

}

void main()

{

HC138init(5);

P0=0x00;

HC138init(4);

P0=0xff;

while(1)

{

SMG_Static();

}

}

每个数码管输出0-9：

#include "reg52.h"

unsigned char code SMDD_duanma[18]={0xc0,0xf9,0xa4,0xb0,

                               0x99,0x92,0x82,0xf8,

                             0x80,0x90,0x88,0x80,

                               0xc6,0xc0,0x86,0x8e,

                               0xbf,0x7f};

void delay(unsigned int t)

{

while(t--);

while(t--);

}

void HC138init(unsigned char i)

{

switch(i)

{

case 4:

P2=(P2&0x1f)|0x80;

break;

case 5:

P2=(P2&0x1f)|0xa0;

break;

case 6:

P2=(P2&0x1f)|0xc0;

break;

case 7:

P2=(P2&0x1f)|0xe0;

break;

}

}

void ShowSMG_Bit(unsigned char dat,unsigned char pos)

{

HC138init(6);

P0=0x01<<pos;

HC138init(7);

P0=dat;

}

void SMG_Static()

{

unsigned char i,j;

for(i=0;i<8;i++)

{

for(j=0;j<10;j++)

{

ShowSMG_Bit(SMDD_duanma[j],i);

delay(60000);

}

}

}

void main()

{

HC138init(5);

P0=0x00;

HC138init(4);

P0=0xff;

while(1)

{

SMG_Static();

}

}

例题：8个数码管分别单独依次显示0-9的值，然后所有数码管一起显示同时显示0-F的值。

#include "reg52.h"

unsigned char code SMDD_duanma[18]={0xc0,0xf9,0xa4,0xb0,

                               0x99,0x92,0x82,0xf8,

                             0x80,0x90,0x88,0x80,

                               0xc6,0xc0,0x86,0x8e,

                               0xbf,0x7f};

void delay(unsigned int t)

{

while(t--);

while(t--);

}

void HC138init(unsigned char i)

{

switch(i)

{

case 4:

P2=(P2&0x1f)|0x80;

break;

case 5:

P2=(P2&0x1f)|0xa0;

break;

case 6:

P2=(P2&0x1f)|0xc0;

break;

case 7:

P2=(P2&0x1f)|0xe0;

break;

}

}

void ShowSMG_Bit(unsigned char dat,unsigned char pos)

{

HC138init(6);

P0=0x01<<pos;

HC138init(7);

P0=dat;

}

void SMG_Static()

{

unsigned char i,j;

for(i=0;i<8;i++)

{

for(j=0;j<10;j++)

{

ShowSMG_Bit(SMDD_duanma[j],i);

delay(60000);

}

}

for(j=0;j<16;j++)

{

  HC138init(6);

P0=0xff;

HC138init(7);

P0=SMDD_duanma[j];

delay(60000);

}

}

void main()

{

HC138init(5);

P0=0x00;

HC138init(4);

P0=0xff;

while(1)

{

SMG_Static();

}

}