LeetCode 39. Combination Sum
Solution1:
DFS,这个套路要熟记啊!
class Solution {
public:
vector<vector<int> > combinationSum(vector<int> &candidates, int target) {
vector<vector<int> > res;
vector<int> out;
sort(candidates.begin(), candidates.end());
combinationSumDFS(candidates, target, 0, out, res);
return res;
}
void combinationSumDFS(vector<int> &candidates, int target,
int start, vector<int> &out, vector<vector<int> > &res) {
if (target < 0) return;
else if (target == 0) res.push_back(out);
else {
for (int i = start; i < candidates.size(); ++i) {
out.push_back(candidates[i]);
combinationSumDFS(candidates, target - candidates[i], i, out, res);
out.pop_back();
}
}
}
};
本文深入解析了LeetCode第39题“组合总和”的解决方案,采用深度优先搜索(DFS)策略,通过递归实现所有可能的组合,以找到目标数值的所有加和组合方式。代码示例清晰展示了如何利用DFS遍历和回溯解决此类问题。
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