Python
class Solution:
def uniquePaths(self, m: int, n: int) -> int:
dp = [[0]*n for _ in range(m)]
for i in range(m):
dp[i][0] = 1
for j in range(n):
dp[0][j] = 1
for i in range(1, m):
for j in range(1, n):
dp[i][j] = dp[i-1][j] + dp[i][j-1]
return dp[m-1][n-1]
Java
法1:二维DP
必须掌握!
class Solution {
public int uniquePaths(int m, int n) {
int[][] matrix = new int[m][n];
Arrays.fill(matrix[0], 1);
for (int i = 0; i < m; ++i) {
matrix[i][0] = 1;
}
for (int i = 1; i < m; ++i) {
for (int j = 1; j < n; ++j) {
matrix[i][j] = matrix[i - 1][j] + matrix[i][j - 1];
}
}
return matrix[m - 1][n - 1];
}
}