Python
class Solution:
def setZeroes(self, matrix: List[List[int]]) -> None:
"""
Do not return anything, modify matrix in-place instead.
"""
i_set = set()
j_set = set()
m = len(matrix)
n = len(matrix[0])
for i in range(0, m):
for j in range(0, n):
if matrix[i][j] == 0:
i_set.add(i)
j_set.add(j)
for i in range(0, m):
for j in range(0, n):
if i in i_set or j in j_set:
matrix[i][j] = 0
Java
法1:自己想的笨蛋方法
class Solution {
public void setZeroes(int[][] matrix) {
Set<Integer> rowSet = new HashSet<>();
Set<Integer> columnSet = new HashSet<>();
for (int i = 0; i < matrix.length; ++i) {
for (int j = 0; j < matrix[0].length; ++j) {
if (matrix[i][j] == 0) {
rowSet.add(i);
columnSet.add(j);
}
}
}
for (int i = 0; i < matrix.length; ++i) {
if (rowSet.contains(i)) {
Arrays.fill(matrix[i], 0);
}
}
for (int j = 0; j < matrix[0].length; ++j) {
if (columnSet.contains(j)) {
for (int i = 0; i < matrix.length; ++i) {
matrix[i][j] = 0;
}
}
}
}
}
// 代码优雅版
class Solution {
public void setZeroes(int[][] matrix) {
int m = matrix.length, n = matrix[0].length;
boolean[] row = new boolean[m];
boolean[] col = new boolean[n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (matrix[i][j] == 0) {
row[i] = col[j] = true;
}
}
}
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (row[i] || col[j]) {
matrix[i][j] = 0;
}
}
}
}
}
作者:力扣官方题解
链接:https://leetcode.cn/problems/set-matrix-zeroes/solutions/669901/ju-zhen-zhi-ling-by-leetcode-solution-9ll7/
来源:力扣(LeetCode)
著作权归作者所有。商业转载请联系作者获得授权,非商业转载请注明出处。
法2:
放个链接,估计真遇到了也写不出来。。。
https://leetcode.cn/problems/set-matrix-zeroes/solutions/670278/xiang-jie-fen-san-bu-de-o1-kong-jian-jie-dbxd/?envType=study-plan-v2&envId=top-100-liked
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