Free DIY Tour
Time Limit: 2000/1000 MS
(Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 635 Accepted Submission(s): 204
Problem Description
Weiwei is a software engineer of ShiningSoft. He has just
excellently fulfilled a software project with his fellow workers. His boss is
so satisfied with their job that he decide to provide them a free tour around
the world. It's a good chance to relax themselves. To most of them, it's the
first time to go abroad so they decide to make a collective tour.
The tour company shows them a new kind of tour circuit - DIY circuit. Each
circuit contains some cities which can be selected by tourists themselves.
According to the company's statistic, each city has its own interesting point.
For instance, Paris has its interesting point of
90, New York
has its interesting point of 70, ect. Not any two cities in the world have
straight flight so the tour company provide a map to tell its tourists whether
they can got a straight flight between any two cities on the map. In order to
fly back, the company has made it impossible to make a circle-flight on the
half way, using the cities on the map. That is, they marked each city on the
map with one number, a city with higher number has no straight flight to a city
with lower number.
Note: Weiwei always starts from Hangzhou(in this
problem, we assume Hangzhou is always the first
city and also the last city, so we mark Hangzhou
both 1
and N+1
), and its interesting point is always 0.
Now as the leader of the team, Weiwei wants to make a tour as interesting as
possible. If you were Weiwei, how did you DIY it?
Input
The input will contain several cases. The first line is
an integer T which suggests the number of cases. Then T cases follows.
Each case will begin with an integer N(2 ≤ N ≤ 100) which is the number of
cities on the map.
Then N integers follows, representing the interesting point list of the cities.
And then it is an integer M followed by M pairs of integers [Ai, Bi] (1 ≤ i ≤
M). Each pair of [Ai, Bi] indicates that a straight flight is available from
City Ai to City Bi.
Output
For each case, your task is to output the maximal
summation of interesting points Weiwei and his fellow workers can get through
optimal DIYing and the optimal circuit. The format is as the sample. You may
assume that there is only one optimal circuit.
Output a blank line between two cases.
Sample Input
2
3
0 70 90
4
1 2
1 3
2 4
3 4
3
0 90 70
4
1 2
1 3
2 4
3 4
Sample Output
CASE 1#
points : 90
circuit : 1->3->1
CASE 2#
points : 90
circuit : 1->2->1
设 dp[i] 为从城市 1 到城市 i 所能够获得的最大 interesting point, 则 dp[i]=max(dp[j]+a[i])(g[j][i]=1,1<=j<i).
代码如下 :