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高中物理复盘：粒子位移计算

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粒子在初速度和恒定加速度下，当速度达到v时，经过时间t后的位移。求在两倍时间内的位移。输入包含多组v和t（-100 <= v <= 100, 0 <= t <= 200），输出对应两倍时间内的位移。" 104356288,9325714,自研可视化搭建系统：降低大屏开发复杂度,"['前端开发', '数据可视化', '组件库', '自研系统', '数据大屏搭建']

Problem B

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Input: standard input

Output: standard output

A particle has initial velocity and constant acceleration. If its velocity after certain time is v then what will its displacement be in twice of that time?

Input

The input will contain two integers in each line. Each line makes one set of input. These two integers denote the value of v (-100 <= v <= 100) and t(0<=t<= 200) ( t means at the time the particle gains that velocity)

Output

For each line of input print a single integer in one line denoting the displacement in double of that time.

Sample Input

0 0
5 12

Sample Output

120

题意：

加速度恒定，在v = at，两倍时间的速度为v = 2at

#include <stdio.h>

int main() {
	int v,t;
	while(scanf("%d%d",&v,&t) != EOF) {
		printf("%d\n",2*v*t);
	}
	return 0;
}