UVA - 10055 Hashmat the brave warrior

最新推荐文章于 2016-08-15 21:55:26 发布

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#Uva #Hashmat the brave wa

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本文介绍了一个简单的程序设计问题，即计算两组士兵数量之间的差值。输入为两组士兵的数量，输出则是它们之间的差值。文章提供了一段C语言代码示例，用于演示如何实现这一功能。

Problem A

Hashmat the brave warrior

Input: standard input

Output: standard output

Hashmat is a brave warrior who with his group of young soldiers moves from one place to another to fight against his opponents. Before fighting he just calculates one thing, the difference between his soldier number and the opponent's soldier number. From this difference he decides whether to fight or not. Hashmat's soldier number is never greater than his opponent.

Input

The input contains two integer numbers in every line. These two numbers in each line denotes the number of soldiers in Hashmat's army and his opponent's army or vice versa. The input numbers are not greater than 2^32. Input is terminated by End of File.

Output

For each line of input, print the difference of number of soldiers between Hashmat's army and his opponent's army. Each output should be in seperate line.

Sample Input:

10 12
10 14
100 200

Sample Output:

2
4

100

题意：

写一个程序要求你计算出两个数差的绝对值。

#include <stdio.h>
#include <stdlib.h>
int main() {
	long long m,n;
	while(scanf("%lld%lld",&m,&n) != EOF) {
		if(n > m)
			printf("%lld\n",n - m);
		else
			printf("%lld\n",m - n);
	}
	return 0;
}