综合强化练习-仓库货物管理（链表、static、对象）

问题描述

• 一个仓库具有 进货和出货两种操作，每个货物有自己的重量，最后统计仓库的总重量，货物的进与出通过终端进行交互。

• 货物与货物之间通过链表连接，这样便于管理，类似于：
  

代码

#include "stdafx.h"
#include <iostream>

using namespace std;

class Goods
{
public:
	Goods(int w):m_weight(w)
	{
		next = NULL;
		total_weight += m_weight;
		cout << "入库了货物重量是：" << m_weight << endl;
	}

	static int Get_Total()
	{
		return total_weight;
	}

	~Goods()
	{
		total_weight -= m_weight;
		cout << "出库了货物重量是：" << m_weight << endl;
	}

	Goods* next;

private:
	int m_weight;
	static int total_weight;
};

int Goods::total_weight = 0;




void Buy(Goods* &head, int weight)  //进货
{
	Goods* new_good = new Goods(weight);
	if (head == NULL)
	{
		head = new_good;
	}
	else
	{
		new_good->next = head;
		head = new_good;
	}
}


void Sale(Goods* &head)  //出货
{
	if (head == NULL)
	{
		cout << "仓库中没有货物了" << endl;
		return;
	}
	else //在头部删除
	{
		Goods* tmp = head;
		head = head->next;     //当最后一个的时候head->next = NULL, 下次再出货上面条:if (head == NULL)就满足
		delete tmp;
	}
}

int main(void)
{

	cout << "1: 进货" << endl;
	cout << "2: 出货" << endl;
	cout << "3: 退出" << endl;

	int weight;
	Goods* head=NULL;

	int choice;
	cin >> choice;
	do
	{
		switch (choice)
		{
			case 1:
				cout << "请输入货物重量" << endl;
				cin >> weight;
				Buy(head,weight);
				break;

			case 2:
				Sale(head);
				break;

		    default:
			    return 0;
		}


		cout << "当前仓库总重量 : " << Goods::Get_Total() << endl;
		cout << endl;
		cin >> choice;
	} while (choice != 3);
	

    return 0;
}

结果：