Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {
public:
int singleNumber(int A[], int n) {
int result = 0 ;
for(int i=0;i<n;++i){
result=result^A[i];
}
return result;
}
};