codeforces：A. The Great Game

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在风雨中奔跑

最新推荐文章于 2023-08-25 11:37:59 发布

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本文介绍了一个特殊的游戏对决问题，通过解析两个队伍的动作序列来决定胜负。每个动作由字符表示，如'8'、'['、'('分别代表石头、剪刀、布。文章提供了C++代码实现，用于判断两组序列的胜负情况。

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Two teams meet in The Game World Championship. Some scientists consider this game to be the most intellectually challenging game in the world. You are given two strings describing the teams' actions in the final battle. Figure out who became the champion.

Input

The input contains two strings of equal length (between 2 and 20 characters, inclusive). Each line describes the actions of one team.

Output

Output "TEAM 1 WINS" if the first team won, "TEAM 2 WINS" if the second team won, and "TIE" if there was a tie.

Sample test(s)

input

[]()[]8<
8<[]()8<

output

TEAM 2 WINS

input

8<8<()
[]8<[]

          output
        

TIE

对于此题表示自己看的时候没有看懂是什么意思，看了一下别人的题解，是石头、剪刀、布。

          AC code：
        

/*
To this question,i am speechless.
looking  other solutions,i don't known the sample test.
*/

#include <string.h>
#include <iostream>
using namespace std;
int main(){
    char str1[20],str2[20];
	while(cin>>str1>>str2)
	{
		int num1=0,num2=0;
		int l1 = strlen(str1);
		int l2 = strlen(str2);
		for(int i=0;i<l1;i+=2){
		if((str1[i]=='8' && str2[i]=='[')|| (str1[i]=='[' &&str2[i]=='(') || (str1[i]=='('&&str2[i]=='8'))
		             num1++;
		else if((str2[i]=='8' && str1[i]=='[')|| (str2[i]=='[' &&str1[i]=='(') || (str2[i]=='('&&str1[i]=='8'))
			num2++;
		}
		if(num1>num2)
			cout<<"TEAM 1 WINS"<<endl;
		else if(num2>num1)
			cout<<"TEAM 2 WINS"<<endl;
		else
			cout<<"TIE"<<endl;
	}
	return 0;
}