Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
The array may contain duplicates.
Have you met this question in a real interview? Yes
Example
Given [4,4,5,6,7,0,1,2] return 0
public class Solution {
/**
* @param num: a rotated sorted array
* @return: the minimum number in the array
*/
public int findMin(int[] num) {
// write your code here
if(num.length==0)
return -1;
int s =0;
int e=num.length-1;
while(s+1<e){
int m= s+(e-s)/2;
if(num[m]>num[e])
s=m;
else if(num[m]<num[e])
e=m;
else
--e;
}
if(num[s]<num[e])
return num[s];
else
return num[e];
}
}