Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {
public:
int singleNumber(int A[], int n) {
int n1 = 0;
for(int i = 0;i<n;++i)
{
n1^=A[i];
}
return n1;
}
};
本文介绍了一种算法,用于在给定整数数组中找到仅出现一次的唯一元素,该算法具有线性时间复杂度且无需额外内存。
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