Codeforce 332C

本文展示了一个使用C++进行编程竞赛的例子,涉及结构体定义、排序算法的应用及多集合的处理等关键技术点。

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#include<cstdio>
#include<algorithm>
#include<set>
#include<queue>
#include<vector>
using namespace std;
#define DEBUG 1
struct element
{
    int index;
    int sort_index;
    int a,b;
    bool operator<(const element &y) const
    {
        return a<y.a;
    }
}x[100010];
bool cmp(element x,element y)
{
    if(x.b == y.b)
    {
        return x.a>y.a;
    }
    return x.b<y.b;
}
multiset<element>S;
vector<int>ans[100010];
vector<int>tmp;
int main()
{
    int n,p,k;
    while(~scanf("%d%d%d",&n,&p,&k))
    {
        for(int i=1;i<=n;i++)
        {
            scanf("%d%d\n",&x[i].a,&x[i].b);
            x[i].index=i;
        }
        sort(x+1,x+n+1,cmp);
        
        S.clear();
        for(int i=1;i<=n;i++)
        {
            ans[i].clear();
        }
        for(int i=p-k+1;i<=n;i++)
        {
            x[i].sort_index=i;
            S.insert(x[i]);
        }
        while(S.size()>k)
        {
            S.erase(S.begin());
        }
        int min_index=S.begin()->sort_index;
        printf("%d",S.begin()->index);
        for(multiset<element>::iterator i=++S.begin();i!=S.end();i++)
        {
            printf(" %d",i->index);
            min_index=min(min_index,i->sort_index);
        }
        while(min_index>=p-k+2&&x[min_index].a == x[min_index-1].a)
        {
            min_index--;
        }
        for(int i=min_index-1,cnt=0;cnt<p-k;i--,cnt++)
        {
            printf(" %d",x[i].index);
        }
        printf("\n");
    }
    return 0;
}
写的很乱,不知道自己写了什么,,就A了
内容概要:本文档为《400_IB Specification Vol 2-Release-2.0-Final-2025-07-31.pdf》,主要描述了InfiniBand架构2.0版本的物理层规范。文档详细规定了链路初始化、配置与训练流程,包括但不限于传输序列(TS1、TS2、TS3)、链路去偏斜、波特率、前向纠错(FEC)支持、链路速度协商及扩展速度选项等。此外,还介绍了链路状态机的不同状态(如禁用、轮询、配置等),以及各状态下应遵循的规则和命令。针对不同数据速率(从SDR到XDR)的链路格式化规则也有详细说明,确保数据包格式和控制符号在多条物理通道上的一致性和正确性。文档还涵盖了链路性能监控和错误检测机制。 适用人群:适用于从事网络硬件设计、开发及维护的技术人员,尤其是那些需要深入了解InfiniBand物理层细节的专业人士。 使用场景及目标:① 设计和实现支持多种数据速率和编码方式的InfiniBand设备;② 开发链路初始化和训练算法,确保链路两端设备能够正确配置并优化通信质量;③ 实现链路性能监控和错误检测,提高系统的可靠性和稳定性。 其他说明:本文档属于InfiniBand贸易协会所有,为专有信息,仅供内部参考和技术交流使用。文档内容详尽,对于理解和实施InfiniBand接口具有重要指导意义。读者应结合相关背景资料进行学习,以确保正确理解和应用规范中的各项技术要求。
### Codeforces Problem or Contest 998 Information For the specific details on Codeforces problem or contest numbered 998, direct references were not provided within the available citations. However, based on similar structures observed in other contests such as those described where configurations often include constraints like `n` representing numbers of elements with defined ranges[^1], it can be inferred that contest or problem 998 would follow a comparable format. Typically, each Codeforces contest includes several problems labeled from A to F or beyond depending on the round size. Each problem comes with its own set of rules, input/output formats, and constraint descriptions. For instance, some problems specify conditions involving integer inputs for calculations or logical deductions, while others might involve more complex algorithms or data processing tasks[^3]. To find detailed information regarding contest or problem 998 specifically: - Visit the official Codeforces website. - Navigate through past contests until reaching contest 998. - Review individual problem statements under this contest for precise requirements and examples. Additionally, competitive programming platforms usually provide comprehensive documentation alongside community discussions which serve valuable resources when exploring particular challenges or learning algorithmic solutions[^2]. ```cpp // Example C++ code snippet demonstrating how contestants interact with input/output during competitions #include <iostream> using namespace std; int main() { int n; cin >> n; // Process according to problem statement specifics } ```
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