Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram.

Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3].

The largest rectangle is shown in the shaded area, which has area = 10 unit.
For example,
Given height = [2,1,5,6,2,3],
return 10.
题意:求直方图中最大面积的矩形。
思路:单调栈的应用。维持一个单调递增的栈,网上写的可以转来:题解
- public class Solution {
- public int largestRectangleArea(int[] height) {
- Stack<Integer> stack = new Stack<Integer>();
- int i = 0;
- int ans = 0;
- int h[] = new int[height.length+1];
- h = Arrays.copyOf(height, height.length+1);
- while (i < h.length) {
- if (stack.isEmpty() || h[stack.peek()] <= h[i])
- stack.push(i++);
- else {
- int t = stack.pop();
- ans = Math.max(ans, h[t] * (stack.isEmpty() ? i : i - stack.peek() - 1));
- }
- }
- return ans;
- }
- }
本文介绍了一种使用单调栈解决直方图中寻找最大矩形面积问题的方法。通过维护一个单调递增栈,算法能够高效地遍历每个柱状条并计算出可能的最大面积。
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