第四次作业

prime = []
yes = 1  # 1为对，0为错
for i in range(2, 1001):
    yes = True
    for j in range(2, i):
        if i % j == 0:
            yes = 0
            break
            if yes == 1:
                prime.appnd(1)

for i in range(1, len(prime)):
    if prime[i] - prime[i - 1] == 2:
        print("(", prime[i - 1], end=',')
        print(prime[i], end=" )\n")

 a = float(input("a="))

b = float(input("b="))

c = float(input("c="))

 

 

def area(side11, side22, side33):

    p = (side11 + side22 + side33) / 2

    s = (p * (p - side11) * (p - side22) * (p - side33)) ** (1 / 2)

    print(f"三角形面积为{s}")

 

    def isvalid(side1, side2, side3):

        if side1 + side2 > side3 and side1 + side3 > side2 and side3 + side2 > side1:

            area(side1, side2, side3)

        else:

            print("输入无效")

 

 

    isvalid(a, b, c)

 

    print(s)

 def reverse(number):

    x = str(number)

    b = x[::-1]

    print(x, b)

    return b

 

def ispalimdrome(number1):

    if reverse(number1) != str(number1):

      print("不是回文数")

    else:

      print(f"{number1}这个数是回文数")

 

 

a = int(input("请输入一个整数"))

ispalimdrome(a)