题意:实现trie树。
题解:
class TrieNode {
public:
char var;
TrieNode* children[26];
bool isword;
// Initialize your data structure here.
TrieNode() {
var = 0;
isword = false;
memset(children,0x0,sizeof(TrieNode*) * 26);
}
TrieNode(char c) {
var = c;
isword = false;
memset(children,0x0,sizeof(TrieNode*) * 26);
}
};
class Trie {
public:
Trie() {
root = new TrieNode();
}
// Inserts a word into the trie.
void insert(string word) {
TrieNode* tmp = root;
int n = word.length();
for(int i = 0; i < n; i++)
{
char c = word[i];
if(tmp->children[c - 'a'] == 0)
{
TrieNode *p = new TrieNode(c);
tmp->children[c - 'a'] = p;
}
tmp = tmp->children[c - 'a'];
}
tmp->isword = true;
}
// Returns if the word is in the trie.
bool search(string word) {
TrieNode* tmp = root;
int n = word.length();
for(int i = 0; i < n; i++)
{
char c = word[i];
if(tmp->children[c - 'a'] == 0) return false;
tmp = tmp->children[c - 'a'];
}
if(tmp->isword) return true;
else return false;
}
// Returns if there is any word in the trie
// that starts with the given prefix.
bool startsWith(string prefix) {
TrieNode* tmp = root;
int n = prefix.length();
for(int i = 0; i < n; i++)
{
char c = prefix[i];
if(tmp->children[c - 'a'] == 0) return false;
tmp = tmp->children[c - 'a'];
}
return true;
}
private:
TrieNode* root;
};
// Your Trie object will be instantiated and called as such:
// Trie trie;
// trie.insert("somestring");
// trie.search("key");