PAT A1058. A+B in Hogwarts (20)

本文介绍了一个基于哈利波特系列小说中魔法货币系统的计算器程序。该程序可以计算两个以加隆、西可和纳特为单位的数值之和,并将结果以相同格式输出。

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PAT A1058. A+B in Hogwarts (20)

If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of “Galleon.Sickle.Knut” (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28
#include <iostream>
#include <algorithm>
#include <vector>


using namespace std;




int main(){

    char str1[100],str2[100];
    long long g1,g2,s1,s2,k1,k2;

    long long res=0,num1,num2;

    scanf("%s",str1);
    scanf("%s",str2);

    sscanf(str1,"%lld.%lld.%lld",&g1,&s1,&k1);
    sscanf(str2,"%lld.%lld.%lld",&g2,&s2,&k2);

    num1 = k1+s1*29+g1*29*17;
    num2 = k2+s2*29+g2*29*17;

    res=num1+num2;

    printf("%lld.%lld.%lld\n",res/(29*17),(res/29)%17,res%29);

    return 0;
}







这里写图片描述

这里注意一下,之前是int类型有一个点通不过,后来改为long long 类型之后,此题可得满分。int的g*17*s*29*k所得的最大结果超过了整型,使用long long类型。

好的,这个测试场景我可以用 Python 的 selenium 库进行自动化测试。以下是大致的测试代码: ```python from selenium import webdriver from selenium.webdriver.common.keys import Keys import time # 登录账户 driver = webdriver.Chrome() driver.get("https://thingsboard.hogwarts.ceshiren.com/") elem = driver.find_element_by_name("username") elem.send_keys("1945075385@qq.com") elem = driver.find_element_by_name("password") elem.send_keys("hogwarts") elem.send_keys(Keys.RETURN) time.sleep(5) # 新增设备 driver.get("https://thingsboard.hogwarts.ceshiren.com/dashboard/3f7d7b20-7b43-11eb-bd5a-3f8ae6b9bcbc") elem = driver.find_element_by_class_name("add-button") elem.click() time.sleep(1) elem = driver.find_element_by_class_name("tb-create-entity-type-select") elem.click() time.sleep(1) elem = driver.find_element_by_xpath("//div[@class='tb-create-entity-type-select']/div[2]/div[1]/div[1]") elem.click() time.sleep(1) elem = driver.find_element_by_class_name("tb-create-entity-form") elem = elem.find_element_by_xpath("//input[@placeholder='Device name']") elem.send_keys("Test Device") elem = driver.find_element_by_xpath("//input[@placeholder='Serial number']") elem.send_keys("123456") elem = driver.find_element_by_class_name("tb-create-entity-footer") elem = elem.find_element_by_xpath("//button[@type='submit']") elem.click() time.sleep(5) # 修改设备 elem = driver.find_element_by_xpath("//span[text()='Test Device']") elem.click() time.sleep(1) elem = driver.find_element_by_xpath("//input[@name='name']") elem.clear() elem.send_keys("New Test Device") elem = driver.find_element_by_xpath("//input[@name='type']") elem.clear() elem.send_keys("New Test Type") elem = driver.find_element_by_xpath("//input[@name='key']") elem.clear() elem.send_keys("New Test Key") elem = driver.find_element_by_xpath("//button[@type='submit']") elem.click() time.sleep(5) # 删除设备 elem = driver.find_element_by_xpath("//span[text()='New Test Device']") elem.click() time.sleep(1) elem = driver.find_element_by_class_name("tb-delete-entity-button") elem.click() time.sleep(1) elem = driver.find_element_by_xpath("//button[text()='Delete']") elem.click() time.sleep(5) # 关闭浏览器 driver.close() ``` 需要注意的是,我使用的是 Chrome 浏览器,所以需要下载对应版本的 chromedriver 并放在系统环境变量中。另外,测试过程中需要等待页面加载,所以我使用了 time.sleep() 函数来进行等待。如果网速较快,可以适当减少等待时间。
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